To check if a number is Armstrong number using java

public class ArmstrongNumber {

    public static void main(String args[]) {
        int n = 0, temp = 0, r = 0, s = 0;
        Scanner in = new Scanner(System.in);
        System.out.println("Enter a number ");
        if (in.hasNextInt()) {
            n = in.nextInt(); // if there is another number 
        } else {
            n = 0;
        }
        temp = n;
        while (n != 0) {
            r = n % 10;
            s = s + (r * r * r);
            n = n / 10;
        }

        if (temp == s) {
            System.out.println(n + " is an Armstrong Number");
        } else {
            System.out.println(n + " is not an Armstrong Number");
        }
    }
}